5y^2+41y-90=0

Solution for 5y^2+41y-90=0 equation:

Simplifying
5y2 + 41y + -90 = 0

Reorder the terms:
-90 + 41y + 5y2 = 0

Solving
-90 + 41y + 5y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-10 + -1y)(9 + -5y) = 0

Subproblem 1
Set the factor '(-10 + -1y)' equal to zero and attempt to solve:

Simplifying
-10 + -1y = 0

Solving
-10 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + -1y = 0 + 10

Combine like terms: -10 + 10 = 0
0 + -1y = 0 + 10
-1y = 0 + 10

Combine like terms: 0 + 10 = 10
-1y = 10

Divide each side by '-1'.
y = -10

Simplifying
y = -10
Subproblem 2
Set the factor '(9 + -5y)' equal to zero and attempt to solve:

Simplifying
9 + -5y = 0

Solving
9 + -5y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + -5y = 0 + -9

Combine like terms: 9 + -9 = 0
0 + -5y = 0 + -9
-5y = 0 + -9

Combine like terms: 0 + -9 = -9
-5y = -9

Divide each side by '-5'.
y = 1.8

Simplifying
y = 1.8
Solution
y = {-10, 1.8}